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Home » Programming » C Programming » Programs » Others » C program to swap two numbers without using a temporary variable
Suryateja Pericherla Categories: Others. No Comments on C program to swap two numbers without using a temporary variable
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In this article we will learn to implement a C program to swap two numbers without using a temporary variable. A C program is provided below which reads two numbers and interchanges them with using a temporary variable.

 

Program is as follows:

//C program to swap two numbers without using a temporary variable
#include<stdio.h>
#include<conio.h>
void main()
{
	int num1, num2;
	printf("Enter first number: ");
	scanf("%d",&num1);
	printf("Enter second number: ");
	scanf("%d",&num2);
	printf("\nBefore swap num1 and num2 are %d and %d",num1,num2);
	num1=num1+num2;
	num2=num1-num2;
	num1=num1-num2;
	printf("\nAfter swap num1 and num2 are %d and %d",num1,num2);
	getch();
}

 

Input and output for the above program is as follows:

Enter first number: 5
Enter second number: 4

Before swap num1 and num2 are 5 and 4
After swap num1 and num2 are 4 and 5

 

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