C program to print a pattern

In this article we will learn to implement a C program to print a pattern. The following C program prints the below pattern for n = 4.

1*2*3*4*17*18*19*20
5*6*7*14*15*16
8*9*12*13
10*11

The program is as follows:

#include <stdio.h>
#include <conio.h>

int main() 
{
	int n = 4;
	int lstart = 1;
	int rstart = 20 - n + 1;
	int dup;
	for(int i = n; i >= 1; i--)
	{
		dup = rstart;
		//Prints left half of the pattern
		for(int j = 1; j <= i; j++)
		{
			printf("%d*", lstart);
			lstart++;
		}
		//Prints right half of the pattern
		for(int j = 1; j <= i; j++)
		{
			printf("%d", rstart);
			if(j != i)
				printf("*");
			rstart++;
		}
		rstart = dup - i + 1;
		printf("\n");
	}
	getch();
    return 0;
}

Output of the above program is as follows:

1*2*3*4*17*18*19*20
5*6*7*14*15*16
8*9*12*13
10*11

Suryateja Pericherla

Suryateja Pericherla, at present is a Research Scholar (full-time Ph.D.) in the Dept. of Computer Science & Systems Engineering at Andhra University, Visakhapatnam. Previously worked as an Associate Professor in the Dept. of CSE at Vishnu Institute of Technology, India.

He has 11+ years of teaching experience and is an individual researcher whose research interests are Cloud Computing, Internet of Things, Computer Security, Network Security and Blockchain.

He is a member of professional societies like IEEE, ACM, CSI and ISCA. He published several research papers which are indexed by SCIE, WoS, Scopus, Springer and others.